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Question

A train moves past a pole and a tunnel 528 m long in 16 seconds and 40 seconds respectively. What is the speed of the train?

  • 40
  • 60
  • 80
  • 100
Answer- C

Let the length of the train be x meters and its speed by y m/sec.

Then, x/y = 16 => x = 16y

Now, (x + 528)/40 = y

=> 16y + 528 = 40y

=> 24y = 528.

y= 22

Therefore Speed = 22 m/sec = ( 22 x 18/5 km/hr) = 79.2 km/hr.