Find the number of three-digit numbers that are divisible by 6?
Question
Find the number of three-digit numbers that are divisible by 6?
The required three-digit numbers would be 102, 108, 114, 120...990, and 996.
The sequence of numbers shows that it is an arithmetic progression, where 'a' = 102, 'd' = 6 and last number = 996
Let the number of terms = n
apply formula n = ((last term - first term)/d) + 1
n = ((996 - 102)/6) + 1
n = (894/6) + 1
n = 150.
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Aptitude