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Question

Jan Shatabdi Express of length 200 meters takes 10 seconds to cross a man who is running at a speed of 10 km/hr in the opposite direction of the Jan Shatabdi Express. What is the speed of the Jan Shatabdi Express?

  • 50
  • 62
  • 74
  • 86
Answer- B

The train and man are moving in the opposite direction so the speed of the train relative to man is the sum of their individual speeds.

Let the speed of the train is X km/hr

Then the relative speed will be: (X + 10) km/hr

In this problem, the other way to find the relative speed is to divide the distance covered (length of train) by the time taken by the train to cross the man.

Relative Speed =200/10 = 20

Relative Speed in Km/hr =20 * 18/5 = 72 km/hr

Now, X+10 = 72

X= 72 − 10= 62 km/hr