Two stations Hyderabad and Warangal are 160 km apart on a straight track. Intercity running from Hyderabad at 8 a.m. at a speed of 30 km/hr towards Warangal. Another Intercity starts from Warangal at 9 a.m. at a speed of 35 km/hr towards Hyderabad. At what time they will meet?

Question

10 a.m
11 a.m
12 a.m
1 p.m

Solutons With Key Points

Answer- B

For convenience let's take Hyderbad as station P and Warangal as station Q

Let the trains meet X hours after the first train starts from station P at 8 a.m.

Distance covered by train starting from station P = speed * time

So, distance = 30 * X = 30X km

Similarly, Distance covered by trains starting from Q = 35 * (X -1) km, as it starts running 1 hour later than the first train.

The distance between the two stations = 160 km

The sum of the distances traveled by both trains to meet each other will be equal to the distance between two stations.

So, 30X + 35 * (X -1) = 160

30X + 35X - 35 = 160

65X = 160 +35

65X = 195

X = 195/65 = 3 hours

It means they will meet 3 hours after the first train starts at 8 a.m. So, they will meet at 8 + 3 = 11 a.m.