30% and 40% of two bottles contain juice. To dilute the juice water is added for the remaining percentage and the total mixture is emptied into a jug. Find the ratio of the Juice and water in the jug?
Question
30% and 40% of two bottles contain juice. To dilute the juice water is added for the remaining percentage and the total mixture is emptied into a jug. Find the ratio of the Juice and water in the jug?
Let the capacity of each bottle = 1
Total capacity of two bottles = 1+1= 2
Quantity of juice in the first bottle = 3/10
Quantity of Juice in the second bottle = 4/10
Total quantity of juice in the two bottles = 3/10 + 4/10 = 7/10
Hence the amount of water in the two bottles = 2 - 7/10 = 13/10
Required ratio of Juice and water = (7/10)/(13/10) = 7/13.
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