For an experiment, a beaker contains a mixture of acid and base in the ratio 7:5. When 9 liters of the mixture is drawn off and the beaker is filled with the base, the ratio of acid and base becomes 7:9. How many liters of acid was contained by the beaker initially?
Question
For an experiment, a beaker contains a mixture of acid and base in the ratio 7:5. When 9 liters of the mixture is drawn off and the beaker is filled with the base, the ratio of acid and base becomes 7:9. How many liters of acid was contained by the beaker initially?
Let Acid be A and Base be B
Suppose the beaker initially contains 7x and 5x litres mixtures A and B respectively
Quantity of A in mix. left =[7x –7/12 * 9 ] =[7x –21/4]
Quantity of B in mix. left =[5x –5/12 *9 ] = [ 5x - 15/4 ]
Therefore [ 7x-21/4 ]/([5x-15/4]+9) =7/9
(28x-21)/(20x+21) = 7/9
252x -189 =140x+147 or 112x =336 , x = 3.
Quantity of A in the can initially =7*3 =21
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