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Question

In a meat market, Shark meat of 700 kg contains water and meat in the ratio of 1:4. How much water must be added to the shark meat mixture so that the ratio of water and meat becomes 3:8?

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  • 60
  • 70
  • 80
Answer- C

Meat in the 700 kg of mixture = 700 ∗ 4/5 = 560 kgs

So, water in the mixture would be = 700 - 560 = 140 kgs

Let water to be added = x ml

Now, (140+x)/560 = 3/8

1120+8x = 1680

8x = 1680 - 1120

8x= 560

X= 560/8 = 70 kg