Saroj has a solution that contains 40% saltwater. A part of the solution gets replaced by another solution which contains 20% saltwater, then the salt percentage becomes 28% after the mixing. What quantity of the solution is replaced?
Question
Saroj has a solution that contains 40% saltwater. A part of the solution gets replaced by another solution which contains 20% saltwater, then the salt percentage becomes 28% after the mixing. What quantity of the solution is replaced?
first solution salt percentage is 40 and a part is replaced with another solution of salt percentage 20 then the mean percentage of saltwater becomes 28
by applying alligation rule
40% (first) 20% (second)
28% (mean)
28-20 = 8% 40-28 = 12
Ratio of first and second in the mixture = 8:12 = 2:3
Now, the quantity of saltwater replaced is equal to the quantity of the second saltwater added.
The quantity of saltwater replaced = 3/5
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